Chemistry
WAEC 2006
An atom
23892X decays by alpha particle emission to give an atom Y. The atomic number and mass number of Y are
-
A.
90 and 234 respectively
-
B.
91 and 238 respectively
-
C.
92 and 236 respectively
-
D.
93 and 238 respectively
Correct Answer: Option A
Explanation
23892 X 234 90Y + 4 2 He Atomic number is 90 while mass number is 234
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}