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An atom 23892X decays by alpha particle emission to give an atom Y. The atomic...

Chemistry
WAEC 2006
An atom 23892X decays by alpha particle emission to give an atom Y. The atomic number and mass number of Y are
  • A. 90 and 234 respectively
  • B. 91 and 238 respectively
  • C. 92 and 236 respectively
  • D. 93 and 238 respectively
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Correct Answer: Option A
Explanation
23892 X 234 90Y + 4 2 He Atomic number is 90 while mass number is 234
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