Determine the amount of electrons needed to deposit 6.4g of copper during the electrolysis of copper (ll) tetraoxosulphate (IV) solution [Cu = 64]

VincentOseiwe

7 years ago

Cu^2+ + SO4^2-
Cu^2+ + 2e- > Cu
:.1g of cu > 2F
64g of cu > 2F
.:6.4g of cu = 2x6.4g/64g
=0.2mole

Atanda Blessing

10 years ago

No Explanation....please we need some explanations......

TonyOmoghene

2 years ago

Cu^2+ +2e^- = Cu
2 mole of electrons liberate or is equivalent to 1 mole of Cu
2 mole of electrons =64g
64g = 2 moles of e^-
1g = 2÷64 moles of e^-
Therefore 6.4g= 2÷64 * 6.4
= 2*0.1 = 0.2 mole.