9.60 g of a gas X occupies the same volume at 0.30 g of hydrogen under the same conditions. Calculate the molar mass of X [H = 1]
8g mol -1
16 gmol -1
32g mol -1
64g mol -1
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my school the selected option is wrong!
the molar mass of hydrogen is 2g/mol not 1g/mol because it is diatomic.
the correct option is D

To explain the answer:
Vapour Density = mass of given vol of gas/mass of equal vol of H2
V.D= 9.60/0.30
V.D = 32
But Molar Mass = V.D × 2
Molar Mass = 32×2 = 64g/mol.

To calculate the molar mass of gas X, we can use the concept of Avogadro's law, which states that:
equal volumes of gases at the same temperature and pressure contain an equal number of molecules.
Given:
mass of gas X = 9.60 g
mass of hydrogen = 0.30 g
Since hydrogen has a molar mass of 2 g/mol (H2), we can calculate the number of moles of hydrogen:
moles of hydrogen = mass of hydrogen / molar mass of hydrogen
= 0.30 g / 2 g/mol
= 0.15 mol
Since gas X occupies the same volume as hydrogen under the same conditions, the number of moles of gas X is also 0.15 mol.
Now, we can calculate the molar mass of gas X:
molar mass of X = mass of X / moles of X
= 9.60 g / 0.15 mol
= 64 g/mol
Therefore, the molar mass of gas X is 64 g/mol.


