How many electrons are removed from Cr2- when it is oxidized to CrO42-?

cayley

9 years ago

Cr2-mean that Cr has two extra electrons. While the o.n of Cr CrO4 2- is x+4(-2)=-2. x-8=-2 x =8-2=6 The o.n of Cr is +6 which means Cr is 6 electrons deficient. Therefore Cr lost 8 electrons.

Eleasha

3 years ago

In the question, Cr^2- has two extra electrons. while in CrO4^2- the oxidation state is calculated as:
Cr + 4(-2) = -2, Cr = -2 + 8 =6. therefore it will have to lose 8 electrons, first to attain O.N. of 0 and then +6

Oluwadaara

2 years ago

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Erumike

4 years ago

The answer is not correct, chromium lost 8 electrons

Oluwadaara

2 years ago

To calculate the number of electrons removed from Cr-2 when it is oxidized to CrO4²⁻, we need to compare the oxidation states of chromium in each compound.

Chromium in Cr-2: Chromium exists in a metallic state with an oxidation state of 0.Chromium in CrO4²⁻: Chromium in the chromate ion (CrO4²⁻) has an oxidation state of +6.

Therefore, 6 electrons are removed from Cr-2 when it is oxidized to CrO4²⁻.

Here's the equation to illustrate the electron transfer:

Cr-2 (0) + 6e- → CrO4²⁻ (+6)

So, the answer is 6 electrons

Amaechi Idam O

9 years ago

I don't understand pls explain well