Which of the following will produce oxygen and hydrogen during its electrolysis using platinum electrode?
Glucose solution
Aqueous copper (ll) tetraoxosulphate (IV)
Dilute sodium chloride solution
Concentrated hydrochloric acid
Dilute copper (ll) chloride solution
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Discussions (5)

the CuSO4 is wrong because copper which is below hydrogen in activity series will be deposited at the cathode. since it is dilute NaCl, Na being above hydrogen in activity series will not be displaced but hydrogen will be deposited and SO4 being above OH- in activity series will not be deposited but oxygen will be deposited. therefore the answer is dilute NaCl

B is wrong, hydrogen will displace copper from its solution at the cathode, making copper and oxygen to be the product, bt opt C, sodium will displace hydrogen,making hydrogen and oxygen d product,

oh mehn pls i'm confused
. i thought the product of electrolysis of dilute NaCl would be hydrogen gas and chlorine gas. Cuz like, hydrogen and chlorine would be discharged while Sodium and oxygen woulg be left

Wait doesn't chlorine attack platinum rods that's why they don't use it for the electrolysis of brine


