Which of the following will produce oxygen and hydrogen during its electrolysis using platinum electrode?

a

Glucose solution

b

Aqueous copper (ll) tetraoxosulphate (IV)

c

Dilute sodium chloride solution

d

Concentrated hydrochloric acid

e

Dilute copper (ll) chloride solution

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Discussions (5)

samadafoo
9 years ago

the CuSO4 is wrong because copper which is below hydrogen in activity series will be deposited at the cathode. since it is dilute NaCl, Na being above hydrogen in activity series will not be displaced but hydrogen will be deposited and SO4 being above OH- in activity series will not be deposited but oxygen will be deposited. therefore the answer is dilute NaCl

Tobscollins
10 years ago

B is wrong, hydrogen will displace copper from its solution at the cathode, making copper and oxygen to be the product, bt opt C, sodium will displace hydrogen,making hydrogen and oxygen d product,

Mariogaji
1 year ago

oh mehn pls i'm confused😭. i thought the product of electrolysis of dilute NaCl would be hydrogen gas and chlorine gas. Cuz like, hydrogen and chlorine would be discharged while Sodium and oxygen woulg be left

Rexconc
2 months ago

Wait doesn't chlorine attack platinum rods that's why they don't use it for the electrolysis of brine

Bemd
2 years ago

what nonsense is this. nacl will never displace hydrogen and oxygen. WRONG

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