What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO2...

WAEC 1997

What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO₂ according to the following equation? C_(s) + O_2(g) → CO_2(g) [O = 16; C =12; 1 mole of a gas occupies 22.4dm³ at s.t.p]

A. 0.224dm³
B. 2.24dm³
C. 4.40dm³
D. 4.48dm³
E. 22.4dm³

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Correct Answer: Option B

Explanation

From the equation, C + O₂ → CO₂ : 22.dm³ of oxygen is required to form 44g of CO₂ the volume of O₂ required to produce 4.4gm is x, :. x = ⁴⁴/₄₄ X 22.4dm³

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