A given volume of methane diffuses in 20 seconds. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [CH\(_4\) = 16; SO\(_2\) = 64]

Mickey007

10 years ago

the correct answer is 40

Myschool Kelly

8 years ago

Thanks for your contributions. Correction has been made

royaldiadem

8 years ago

The correct answer is 40 because, using Graham's law of diffusion which states=>R1/R2=\|M2/M1,
you eventually get 20/R=2..... :. R=20*2=40

doctormmusa

10 years ago

thanks

prince hamsel

10 years ago

The selected answer is wrong:

from page 90 new school chemistry. R1/ R2=√M2/M1. when a certain volume of methane diffuse in 20 second, and same volumes of SO2 diffuses, the time it takes is 40 seconds. PROVE= let the vol be x. x/20\x/t. where t is the time of diffusion of SO2. x/20/x/t=√64/16. then t/20=8/4, t=40

Verabidex

9 years ago

Correct answer is 40 plssss