What amount of copper is deposited when 13.0g of zinc reacts with excess copper (ll) tetraoxosulphate (IV) solution according to the following equation? Zn _(s) + CuSO_4(aq) → ZnSO_4(aq) + Cu _(s) [Cu =63,5, Zn = 65]

knifesama

3 years ago

1 mole of zinc = 1 mole of copper
65 - 63.5
13g - x
Cross multiply
65x = 825.5
x = 12.7g
no of moles = reacting mass/molar mass
nom = 12.7/63.5
n = 0.2 moles

Lordoverit

2 years ago

the answer is 0.1mole, you ought divide it by the valence electron of copper