What volume of carbon (lV) oxide is produced at s.t.p. when 2.5g of CaCO3 reacts with excess acid according to the following equation? CaCO3 + 2HCI → CaCI2 +H2O + CO2 [CaCO3 = 100; molar volume of a gas at s.t.p = 22.4dm3]

a

11.20dm3

b

5.60dm3

c

2.24dm3

d

0.56dm3

e

0.28dm3

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Correct Option
d

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Sarif
3 years ago

22.4 × 2.5 = 56

56÷100 = 0.56 ❤🤗

Stephenpee
1 year ago

They should show their solves

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