Correct Answer: Option C

Explanation

So during the presence of methane, sodium ethanoate with soda lime is used, using sodium propanoate with sodium will produce ethane according to the equation below

\(\CH_3CH_2COONa + NaOH → C_2H_6 + Na_2CO_3\)\ + CO\(_2\)

There are two gases but from the options provided, ethane is the correct answer.

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