How many faradays of electricity are required to liberate 9g aluminium? (AI = 27)
a
0.1
b
0.3
c
1.0
d
2.7
e
3.0
Explanation
Correct Option
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Discussions (5)
ndiwecharles
10 years ago
Aluminium is liberated as AL^3+ + 3e ~~~> AL 29g of AL requires 3 faraday 9g = ? 9*3/27 = 1F.
Babliwa
2 years ago
N= g/rmm
9/27=0.333moles
If 9g=====0.333
27g=======?
27*0.333=8.999/9= 0.99
This is approximately 1F
