The product of the reaction between ethanol and excess acidified K\(_2\)Cr\(_2\)O\(_7\) is

Alice360

3 years ago

the answer is ethanal because ethanol is readily oxidized to ethanal by warming with k2cr2o7 it is on further oxidation in the presence of excess h2so4 the ethanal is converted to ethanoic acid

Ndukajoseph

4 years ago

C2H5OH +O=CH3CHO +H2O
CH3CHO+O=CH3COOH +H2O
Where O is K2CR2O7

Ndukajoseph

4 years ago

I hope that enough to understand.

maduozorsopuruchi

5 years ago

Pls can someone explain oo

Praise1234567890

4 years ago

The answer is ethanal (A)

SavageJoonie

1 year ago

The product of the reaction between ethanol and excess acidified K2Cr2O2 is ethanal not ethanoic acid. Ethanoic acid is prepared by the complete oxidation of ethanol by acidified sodium heptaoxochromate(VI) solution.

Dynamiclady

4 years ago

How
don't you understand ni