a
SnCI2
b
SnCI4
c
SnO2
d
SnH4
e
Sn(OH)2
Explanation
Correct Option
dNo explanation available
Video Explanation
No video available
Post your Contribution
Share:
Discussions (3)
Emmy1234
9 years ago
tin(ii) ion are good reducing agent so it a since s+2(-1)=0
s=+2 and are more easily oxidized to tin(iv) compound so A is the answer
