What volume of distilled water should be added to 400cm3 of 2.0 mole dm-3 \(H_{2}SO_{4}\) to obtain 0.20 mole dm-3 of solution>
600cm-3
800cm-3
1,000cm-3
3,600cm-3
4,000cm-3
Explanation
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Discussions (8)
the ansa is e, thus: c1v1=c2v2
.: 400×2=0.2v,
800=0.2v divide through by 0.2
800÷0.2=v
v=4000cm^3
the equation for the: H2SO4+H2O~HSO4+H3O
We can solve this using the dilution formula:
C_1 V_1 = C_2 V_2
where:
mol/dm³ (initial concentration)
cm³ (initial volume)
mol/dm³ (final concentration)
= final volume (to be determined)
Step 1: Solve for
(2.0 \text{ mol/dm}^3) \times (400 \text{ cm}^3) = (0.20 \text{ mol/dm}^3) \times V_2
800 = 0.20 V_2
V_2 = \frac{800}{0.20} = 4000 \text{ cm}^3
Step 2: Calculate the volume of distilled water to be added
\text{Water to add} = V_2 - V_1 = 4000 - 400 = 3600 \text{ cm}^3
Answer:
D. 3600 cm³
