What is the number of oxygen atoms in 32g of the gas? (O = 16, L = 6.0 X 10\(^{23}\) mol\(^{-1}\))
3.2 X 10 23
6.0 X 1023
1.2 X 1024
1.6 X 1024
2.0 X 1024
Explanation
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Discussions (17)
The answer is wrong because of the oxygen atoms in the question so 32/32 is 1 so therefore 1 mole will occupy 6.02*1023
i agree wii you @lahmbhe..oxygen gas has 2 atom..32/32..1 mole gives the answer B..
@myschool the selected answer is wrong, according to avogadro, one mole of any substance contains 6.o2 X 10^23 entities ( atoms or molecules), and since one mole of Oxygen is 32g (NOTE: Oxygen is diatomic) then 32g of Oxygen should contain 6.02 X 10^23 atoms and not the other way round
My School pls correct this the answer is wrong it's supposed to be 6.02×10^23 which is Option B Oxygen atom is O2 please change it
oluwashida. U are right,de correct answer is C. we hav to find de moles b4 knowing de numba of oxygen atoms
My school, the correct answer is C because we ought to firstly calculate MOLE =32/16=2mole. So after this, to calculate the number of atoms =number of mole × the Avogadro "s constant (L) i.e 2× 6.0*10^23= 1.2×10^24 .That's option C.
