If the volume of a given mass of gas at 298 K and pressure of 205.2 x 10\(^3\) Nm\(^{-2}\) is 2.12dm\(^3\), what is volume of the gas at s.t.p? (Standard pressure = 101.3 x 10\(^3\) Nm\(^{-2}\), Standard temperature = 273K)

GirllikeOma

3 years ago

There was even a mistake in de figures with de solving

Davesf

10 months ago

the answer is 3.93

dannyartz

3 years ago

The answer should be 3.93 not 4. 4 is not even among the option.

Utakong

3 years ago

P1v1/T1=p2v2/T2
205.2*10^3*2.12*273/298*101.3*10^3=
118761.55/30187.4=3.93

Sulaimontoheeb24

4 years ago

There should be working

Leohh

7 months ago

As how na

Ans:3.93dm3

Veeofficial

3 years ago

The answer is exactly 3.93 not 4