2NaNO3 → 2NaNO2 + O2. From the equation above, what is the volume of oxygen produced at s.t.p. when 8.5g of 2NaNO3 is heated until no further gas is evolved? (2NaNO3 = 85, molar volume of gases at s.t.p. = 22.4dm3)

Prince Nemerem

9 years ago

Going with the explanation above, the answer is actually 2.24 which is 'B' not 'A'

rayhenry82

10 years ago

Myschool.u can't jst is simple..please try and show solving cos some people may not know d solution...

Kenhinde

4 years ago

Why my school,why,I got the answer 😭😭.The answer B

Esse007

5 years ago

the answer is B oo , pls make correction

Kobichukwudi11

4 years ago

They Found the volume of NaNO3 liberated not oxygen as asked in the question

Kaulohpoli

2 months ago

my school is actually correct
and we are also correct in a way

the problem came from the question
2 moles of NaNO2 is 170g not 85
1 mole = 85

think dats where the problem came from

vivian279

4 years ago

The answer is B not A
And there is no given explanation

RiverHeights

2 years ago

It should be B.
2 mol > 1 mol
85 > 1 mol
8.5 > 0.1 mol

Vol = No of moles * 22.4dm³
Vol = 0.1 * 22.4dm³
Vol = 2.24dm³

VPETERS2002

5 years ago

Answer:B

85g=22.4dm3
8.5g=(8.5*22.4)/85=2.24dm3(answer)