CH4(g) + 2O2(g) → 2H2O(l) + CO2(g) ∆H = 890KJ mo-1 ∆H in the reaction represented by the equation above is the enthalpy of

a

formation

b

combustion

c

solution

d

activation

e

neutralization

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Discussions (3)

Samuel.og
4 years ago

COMBUSTION GIVES OUT HEAT
SO THE DELTA H= -890 NOT 890

Narutocharl
1 year ago

The ans is wrong cos combustion is exothermic and enthalpy change for exothermic rxn should be negative so the ans should be enthalpy of formation

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