What is the amount (in mole) of sodium trioxocarbonate (IV) in 5.3 g of the compound? (Na₂CO₃ = 106)

Oluwadecent

9 years ago

Here is an explanation:

Conc. in mole = conc. in gram/molar mass

conc. in mole = 5.3/106

conc. in mole = 0.05mol/dm~3

anadebec

10 years ago

Here is an explanation:

no of moles=reacting mass/molar mas i.e 5.3/106=5.6.....

REF: new school chemistry