The decomposition of hydrogen peroxide is represented by the equation: 2H2O(l) + O2(g) what mass of hydrogen peroxide would be required to produce 22.4dm3 of oxygen at s.t.p? (H = 1, O = 16, molar volume of a gas at s.t.p. = 22.4dm3)
a
18 g
b
34 g
c
36 g
d
64 g
e
68 g
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Discussions (7)
Habibullah123
4 years ago
The correct answer is D because
The equation is 2H2O2=2H2O+O 1mole of oxygen is produce by decomposition of 2H2O2 22.4dm3 of oxygen measured at s.t.p is 1 mole of oxygen so M= nMr moles of H2O2 are needed 2×34=64
King33Victor
2 months ago
n = volume (dm^3)/22.4dm^3
n= 22.4/22.4
=1
also recall that
n = m/mm
1 = m/H2O2
1= m/2+32
1 = m/34
m = 34g.
