To what temperature must a gas be raised from 273K in order to double both its volume and pressure?``

a

298k

b

300k

c

546k

d

819k

e

1092k

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Correct Option
e

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from d eqn p1v1/T1=p2v2/T2,T1=273K,V2=2V1,P2=2P1.Therefore T2=P2V2TI/P1V1 =2P1*2v1*273/p1v1=4*273=1092.hope its clear

fortunez
10 years ago

could someone explain this solution... thanks

deymolah
10 years ago

somebody should explain it plz

samlet
10 years ago

273/2=136.5

136.5+273=409.5

408.5×2=819

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