How many mole of AgNO\(_3\) are there in 500cm\(^3\) of 0.01M AgNO\(_3\) solution?
Given:
V = 500 cm\(^3\)
C = 0.01M
n = ?
The relationship among the three parameters is n = \(\frac{CV}{1000}\)
n = \(\frac{0.01\times 500}{1000}\)
n = 0.005 mole
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