In the reaction represented by the equation; 2FeCI3 + SO2 + 2H2O → 2FeCL2 + H2SO4 + 2HCI the oxidation number of sulphur changes from
a
+2 to + 6
b
+ 4 to + 6
c
0 to + 6
d
- 2 to + 4
e
+2 to + 4
Explanation
Correct Option
bNo explanation available
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Shu_gar
5 years ago
oxidation number of oxygen is -2.
so from the LHS,
lets assume the oxidation number of sulfur to be X.
X + (-2 × 2moles of oxygen) = 0
X + (- 4) = 0.
moving (-4) to tge other side.
X becomes +4.
sulfur therefore,has an oxidation number of +4 in SO2.
from the RHS ;
no need to stress it.
the name alone already tell you the oxidatuon number of sulfur.
Hydrogentetraoxosulphate(VI)
in other words the oxidation number of sulfur in H2SO4 is +6.
