120cm\(^3\) of hydrogen were sparked with 60cm\(^3\) of oxygen at 110\(^o\)C. What was the volume of steam produced? The equation for the reaction is
2H\(_2\)(\(_g\) + O\(_2\)(\(_g\) → 2H\(_2\)O\(_g\)
According to Gay-Lussac's Law of Combining Volumes, it states that when gases react, their volumes combine in a simple whole-number ratio, provided the temperature and pressure are constant.
Consequently, 2H\(_2\)(\(_g\) + O\(_2\)(\(_g\) → 2H\(_2\)O\(_g\)
2 : 1 : 2
120cm\(^3\): 60cm\(^3\) : 120cm\(^3\)
Hence, 120cm\(^3\) of steam was produced.
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