The reaction represented by the equation C(s) + H2O(l) → CO(s) + H 2(s) was carried out at 27oC if the enthalpy change was + 4500 J and the entropy change was + 12J, what was the free energy change? (∆G = ∆H - T∆S)
a
- 4176 J
b
+4176 J
c
- 900 J
d
+ 900 J
e
+8100 J
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Samueloviesu
5 years ago
The answer is D.
Convert the 27°C to kelvin by adding 273 to it
T=27+273=300K
∆G=∆H - T∆S
∆G=4500 - 300(12)
=4500-3600
∆G=900J
