What quantity of silver is deposited when 96500C of electricity is passed through a solution containing silver ions? (Ag = 108, 1F = 96500C)

asulewon omalabake

9 years ago

Here is an explanation:

since 1F=108g

96500c=(x)g

cross multiply,

x=96500*108/96500

X=108g

REF: check new school chemistry(osei yaw ababio) page 209

sufyanice

9 years ago

correct...use ds simple trick formula....Q=m x f/Mm whr 'Q' is d quantity, 'm' d mass 'f' faraday no. And 'Mm' molar mass. since u're looking for quantity of Ag=d mass den make 'm' d subject formula nd solve

Pearltems

4 years ago

M/Mm = Q/ F
M/108 = 96500/96500
96500M =96500 X 108
96500M =10422000
M =10422000 /96500
M =108g

BZKID

4 years ago

the quantity of silver is deposited when 96500 colums of electricity is kassed through a solution containing silver ions (Ag=1 farade=96500)

BZKID

4 years ago

0.222g Of A Divalent Metal Is Deposited When A Current Of 0.45 Amperes Is Passed Through A Solution Of It's Salt For 25 Minutes Using Appropriate Electrodes. Calculate The Relative Atomic Mass Of The Metal

godemmy1234

1 year ago

yes