The sulphide which is insoluble in dilute hydrochloric acid is

a

FeS

b

CuS

c

ZnS

d

Na2S

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Explanation

Correct Option
b

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Discussions (8)

chidera Malachy
9 years ago

Here is an explanation:

this is because Cu can not displace H in its solution

reason being that H is above Cu in the electrochemical series

REF: check new school chemistry,page 220

Allsaint
10 years ago

Pls ooo...myschool this is very wrong...the answer is CUS because CuS cannot displace hydrogen from hydrochloric acid.reason(it is lower in electrochemical series.

Myschool Kelly
10 years ago

Thanks for your contributions. Correction has been made.

obedvictor
9 years ago

Yeah oo,B is d answer

Tonio13
10 years ago

INCORRECT.THE ANS IS B @essential chem txt bk(summary of d solubity of sulphides in water and dil.HCl).

victorchidubem
11 years ago

the correct answer is B

John00777
2 years ago

The correct answer is D, Na2S! πŸ§ͺ

Remember that the question asked about the sulfide that is insoluble in dilute hydrochloric acid. Na2S is that sulfide because Na2S does not dissolve in dilute HCl. Instead, a layer of solid Na2S forms on the surface of the acid. This is because sodium (Na) forms soluble chlorides, unlike CuS, which dissolves in HCl to form soluble copper chloride.

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