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On heating, which of the following compounds will decompose to the free metal, nitrogen (IV)...

Chemistry
JAMB 2006

On heating, which of the following compounds will decompose to the free metal, nitrogen (IV) oxide and oxygen?

  • A. Ca(NO3)2
  • B. Cu(NO3)2
  • C. AgNO3
  • D. NaNO3
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Correct Answer: Option C
Explanation

When calcium nitrate (Ca(NO\(_3\))\(_2\)) decomposes on heating, it produces calcium oxide (CaO), nitrogen dioxide (NO\(_2\)) gas, and oxygen gas (O2). 

Chemical equation: 2Ca(NO\(_3\))\(_2\) → 2CaO + 4NO\(_2\). + O\(_2\).. 

When copper nitrate (Cu(NO\(_3\))\(_2\)) decomposes on heating, the products formed are copper oxide (CuO), nitrogen dioxide (NO\(_2\)), and oxygen gas (O2). This is a thermal decomposition reaction where the copper nitrate breaks down into these components when heated. 

Chemical equation: 2Cu(NO\(_3\).)\(_2\)) → 2CuO + 4NO\(_2\). + O\(_2\). 

When silver nitrate (AgNO\(_3\)) decomposes on heating, the products formed are silver metal (Ag), nitrogen dioxide (NO\(_2\)), and oxygen (O\(_2\)). 

Chemical equation: 2AgNO\(_3\) (s) → 2Ag (s) + 2NO\(_2\) (g) + O\(_2\).(g). 

When sodium nitrate (NaNO\(_3\)) decomposes on heating, it produces sodium nitrite (NaNO\(_2\)) and oxygen gas (O2) as the primary products; essentially breaking down into these two simpler substances. 

Chemical reaction: 2NaNO\(_3\) → 2NaNO\(_2\) + O\(_2\). 

There is an explanation video available below.


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Explanation Video

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