The IUPAC nomenclature for the compound above is

a

4-methylpent-1-ene

b

3-methylpent-2-ene

c

2-methylpent-1ene

d

2-methylpent-4-ene

Download Offline App Ask a Question

Explanation

Correct Option
a

Video Explanation

Post your Contribution

Share:

Discussions (10)

Odemosad
1 year ago

Functional group have Priority to the Alkyl Group, Hence start from the Right.

Answer: 4-methylpent-1-ene

KennyBrain10
1 year ago

Count from the side that will the double or triple bond a lower number

Moneymoney
11 years ago

Queennette2
3 years ago

abegggg
Do u start counting 4rm d side closest to the substitutuent or double bond?

korede_ari80
2 years ago

No diagram

Keemyong
7 years ago

The correct option is D because, on Alkene family we don't 1which is methene,so the correct IUPAC nomenclature is 2-methylepent-4- ene.😄😑

Quick Questions

Ask a Question
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments

infinitehoaxx

21st May, 2026

Computer


4 comments