The structure comprises a benzene ring ( C\(_6\)H\(_5\) ) with a CH\(_2\)-CH\(_3\) substituent attached to it.
Recall that benzene is aromatic compound, as well as conjugated compound having three double bonds and three single bonds.
If we re-write the molecular formular of the compound,trying to represent on a straight chain just for better understanding, we'll have -CH=CH-CH=CH-CH=CH-CH\(_2\)-CH\(_3\)
Whenever you are solving questions on Hybridization of Hydrocarbons, always use this key:
If the compound contains a Carbon atom + single bonded to 4 atoms - SP\(^3\)
If the compound contains a Carbon atom + one double bond + two single bonds - SP\(^2\)
If the compound contains a Carbon atom + a triple bond + one single bond - SP
SP\(^2\) SP\(^2\) SP\(^3\)
-CH=CH-CH=CH-CH=CH-CH\(_2\)-CH\(_3\)
There's no triple bond, hence there will be no SP hybridization but we only have SP\(^3\) an SP\(^2\) because of the criteria stated above.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}