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B
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D
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Discussions (21)
i dont get it i thought Na is acting as a catalyst so why is it on the product side of the equation
Given Reaction:
CH₃–C≡CH (Propyne)
Reagent: Na in liq. NH₃
What’s going on here?
This setup is typical of Birch-type partial reduction of alkynes using sodium metal in liquid ammonia, which gives trans-alkenes.
So:
{CH₃–C≡CH}=>{Na / liq. NH₃}will give {CH₃–CH=CH₂}
This means:
• The triple bond is reduced to a double bond
• The product is propene (CH₃–CH=CH₂)
Now, check Option B:
Option B shows:
CH₃–CH=CH₂
Yes! That’s propene, which is exactly the major product of the partial reduction of propyne with Na/NH₃.
Final Conclusion:
Yes — Option B is correct.
Correct Answer: B
dem say the sodium and ammonia will not be part of d product so where did the hydrogen came from in the product
