The times taken for iodine to be liberated in the reaction between sodium thiosulphate and hydrochloric acid at various temperature are as follows. These results suggest that
for a 10o rise in temperature, rate of reaction is double
for a 10 o rise in temperature, rate of reaction is halved
time taken for iodine to appear does not depend on temperature
for a 10 o rise in temperature rate of reaction is tripled
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (24)
@Aliyu
ur very correct
Pls As the time decreases, rate of reaction increases
Let us not confuse ourselves
my school should please pay attention to the complaints of its users and make corrections as soon as possible
@myschool the answer is A because rate of reaction is inversely proportional with time and since time was given in the table (i.e halved per 10 degree rise ) the rate would be doubled✔️✔️💯💯
At 25°C, time = 72 seconds
At 35°C, time = 36 seconds
At 45°C, time = 18 seconds
From this, we can see that for every 10°C increase in temperature, the time taken is halved. The rate of reaction is inversely proportional to the reaction time, so when time is halved, the reaction rate doubles.
Thus, the correct answer is:
A) For a 10°C rise in temperature, the rate of reaction is double.
Apologies please! Kindly note that the question has been reviewed.
Thank you all for your contributions.
Admin, the answer is A. For a 10 percent increase in temperature, the reaction occurs twice as fast. Therefore, the rate of reaction doubles.
@Aliyu, answer questions according to information given, temperature and time were given not rate of reaction,with the information we should be able to come across the correct answer.
The time halves but the rate doubles because rate is inversely proportional to the time.
The answer is A. the reaction rates doubles for each rise of temeperature by 10degree celsius
REF:New school chemistry page 260
It should be halved not doubled cuz for an increase in temperature the time was going down not up
