In the solubility curve above, water at 98\(^0\)C is saturated with KCl and KCIO\(_3\). What is the percentage of KCl impurity in the crystals formed when the solution is cooled to 30\(^0\)C?

a
51.5
b
45.5
c
34.5
d
26.5
Explanation
Correct Option
dVideo Explanation
No video available
Post your Contribution
Share:
Discussions (21)

yaboagye
1 year ago
KCl crystallized = Solubility at 98oC – Solubility at 30 oC = 55 – 37 = 18
KClO3 crystallized = Solubility at 98oC – Solubility at 30 oC = 55 – 5 = 50
% KCl = 18/(50 + 18) × 100% = 26.47%

jennifersolomon1124
1 year ago
Your solving is correct but how did you arrive at your answer with that formula. I mean the formula is correct but the way you positioned the figures isn't. Pls check it again.







