In the solubility curve above, water at 98\(^0\)C is saturated with KCl and KCIO\(_3\). What is the percentage of KCl impurity in the crystals formed when the solution is cooled to 30\(^0\)C?

a

51.5

b

45.5

c

34.5

d

26.5

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Explanation

Correct Option
d

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Discussions (21)

Erica1739
2 years ago
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yaboagye
1 year ago

KCl crystallized = Solubility at 98oC – Solubility at 30 oC = 55 – 37 = 18
KClO3 crystallized = Solubility at 98oC – Solubility at 30 oC = 55 – 5 = 50

% KCl = 18/(50 + 18) × 100% = 26.47%

Bboyz
9 years ago

Diagram iz f** kin nt clear

Refhord
3 years ago

My school pls help us with the answer 😭😭

OjeD
6 years ago

Give is some answers na.. Why are you guys doing like this... 🙄🙄

Your solving is correct but how did you arrive at your answer with that formula. I mean the formula is correct but the way you positioned the figures isn't. Pls check it again.

humbleuche
1 year ago

you guys hardly explain questions. you give the answers

Sammyporsche123
2 years ago

trace 30 degree celsius

Domnickado
3 years ago

MYSCHOOL the answer is meant to be D. I don't just have the time to explain.

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