The solubility curve of a solid X (molecular mass = 160) is as show above. 1,000 cm3 of a saturated solution of X at 80°C is cooled to 40°C . The weight of X crystalized out would be

Etugo

10 years ago

Ook...

Diff in mol =0.4-0.3=0.1mol

Mol=mass/molar mass

0.1=mass/160

Mass=0.1x160=16g

wsagvasdghvd

7 months ago

here you goo

Silveradero

1 year ago

look at the diagram 80°c if u follow the lineit will give u 0.4 mol and 40°c if u follow the line u will get 0.3mol

Etugo

10 years ago

Solution, PLS

newton141

7 years ago

agree

efegiemu

9 years ago

chucks thank you god bless you

Refhord

3 years ago

Understood

chombo

1 year ago

How do they get 0.4 and 0.3? any o

jaseradjuafunog

10 years ago

Here is the correct explanation:

not really i dont understand how to arrive at the answer can anyone help

Ikenna1989

1 year ago

At 80°C = 0.3, At 40°C = 0.4
On cooling, 0.4 - 0.3. = 0.1mol.

But, solubility = mass/ molar mass X 1000/vol.

Then, 0.1mol = mass/160 X 1000/200
1000/ 200 = 5

0.1mol = mass /160 X 5
let mass = M

0.1mol = 5M/160
5M = 0.1 X 160

Divide both sides by 5

5M/ 5 = 0.1 X 160/5

M = 0.1X 160/ 5.
= 3.2g.