Copper sulphate solution was electrolysed using the apparatus show above. Which of the following changes are observed?
The bulb lights and copper is deposited at both electrodes
the bulb lights and copper is deposited at the anode and disappears from the cathode
the bulb lights and copper is deposited at the cathode and oxygen liberated at the anode
the bulb lights and copper is deposited at the cathode and disappears from the anode
the bulb lights but no additional changes are observed
Explanation
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In ELECTROLYTIC CELLS, anode is Positive and cathode is negative but for that of ELECTROCHEMICAL CELLS, it's inverse, anode is negative and is Positive.
Therefore, under electrolytic cells, the cations move to the anode and the anions move to the anode. Since, CuΒ²+ is a cation it will move to the cathode and disappears from anode where the current enters into the solution of CuSO4. ποΈποΈππ
The correct answer is C. the bulb lights and copper is deposited at the cathode and oxygen is liberated at the anode. During the electrolysis of copper sulphate solution:
Cathode (Negative Electrode): Copper ions (Cu^2+) are reduced to copper metal (Cu) and are deposited on the cathode.
Anode (Positive Electrode): Water molecules are oxidized to form oxygen gas (O_2) and hydrogen ions (H^+), with oxygen being liberated at the anode.
This process is demonstrated in the simple diagram of the electrolysis experiment setup shown in the image. The bulb lighting up indicates that the circuit is complete and current is flowing through the electrolyte.
