Which of the following is the correct order in the above diagram increasing boiling point, of the isomeric \(C_{5}H_{12}\) compounds?

biganimal

3 years ago

This is it!
The more the branching, the lower the boiling point. Pentane is not branched at all, therefore it has the highest boiling point; 2,2-dimethylpropane is the most branched, therefore it has the lowest boiling point.

eruditemezie

7 years ago

hi

Chopin

6 years ago

Dey got no diagram

Shemasane19

4 years ago

The increase in number of carbons will increase the boiling point. 🖊️😒

helenobii

5 years ago

boiling point increases with increase in atomic number

Joseph247joel

3 months ago

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T01u

2 years ago

Incorrect diagrams

Goodness00000

4 years ago

I love this kain question🍿🤭

Soloxxx2000

1 year ago

I'm guessing the straighter the carbon chains,the higher it's boiling point

SLAZE5

1 year ago

😐🙂

CenSmart

6 years ago

n-pentane,H3CCH2CH2CH2CH3 , 36 °C;

isopentane,(H3C)2CH2CH2CH3,27.8 °C;

neopentane,(H3C)4C,9.5 °C. Correct answer is D

g9ifted006

2 months ago

I thought it was supposed to be the higher the branch the higher it's boiling point