\(Zn + H_2 SO_4 → ZnSO_4 + H_2\)

in the above reaction, how much zinc will be left undissolved if 2.00g of zinc is treated with 10cm^3 of 1.0 M of \(H_2SO_4\)?
[Zn =65, s = 32, O = 16, H = 1]

ifyanunike

4 years ago

V=10cm3=0.01dm3
C=1moldm-3
n=Cv
n= 1*0.01
n=0.01mol
n=m/M
therefore m=n*M
Molar mass of zinc is 65gmol-1
m=0.01*65
m=0.65g
Mass of undissolved zinc is 2-0.65
=1.35g

Olefin

5 years ago

Incomplete question

Alisha101

2 years ago

Please how did you get this can't u explain

Gddhhcv

2 years ago

I didn't understand 😔

Omimi

7 years ago

I think its E