3. 06 g of a sample of potassium trioxochlorate (V) (KCIO\(_3\)) was required to make a saturated solution with 10cm\(^3\) of water at 25°C. The solubility of the salt at 25°C is [K =39, Cl = 35.5, O = 16]

Saint.Vincent

6 years ago

Molar mass of KClO3 = 122.5 g/mol
since 3.06g are dissolved in 10cm3
xg will be dissolved in 1000cm^3×3.06g/10cm3 = 306g
meaning 306g/dm3
but Molar conc = Mass conc/Molar mass
then we have 306gdm^3/122.5gmol^ = 2.497mol/dm3
C is the answer

fmeka27

11 years ago

Solubility = mass/molar mass X 1000/volume

Do the math.

Raphael1959

9 years ago

Actually d ansa is correct but d question is wrong cause d chemical formula 4 d compound used is wrong it's KCLO3 not KCLO so DAT means d R.M.M will 122.5 not 90.5

Etugo

10 years ago

Molar mass of KClO=90.5

mass=3.06

mole=3.06/90.5

=0.0338

if 10cm3=0.0338

then 1000=y

y=(1000x0.0338) /10

y=3.38moldm-3

~~B

Etugo

10 years ago

The selected answer is wrong:

Check my calculations above

REF: Ababio

artist101

4 years ago

i got a question right and you wronged it