2.5 g of a hydrate barium salt gave on heating, 2.13 g of the anhydrous salt. Given that the relative molecular mass of the of the anhydrous salt is 208, the number of molecules of water of crystallization of the barium salt is
10
7
5
2
1
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2.5/2.13==208+18X/208
CROSS MULTIPLY
2.5*208=2.13(208+18X)
520=443.04+38.34
520-443.04=38.34X
76.96=38.34X
DIVIDE BOTH SIDES BY 38.34
76.96/38.34==2.00
it could also be like this
x= M (H - A)/18A
=233.33 ( 2.5-2.13 )/18×2.13
=2
where= 233.33 is the Molar mass of barium salt(BaSO4)
And 18= Molar mass of water H2O
Firstly you minus the mass of barium to the mass of anhydrous salt you will get 0.37 now to get the miles . Reacting mass divided by molar mass equals to 0.37/208 = 1.77 approximately 2
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