log 10[OH-]
log 101/[H 3 O+]
log 10[H 3 O+]
log 101/[OH -]
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Discussions (15)

B is correct.
It's just the inverse of its normal value.
Law of logarithm in action.
First, we can actually say H3O+ is the same as H+.
Hence, pH can as well be -Log [H3O+]
Now, from the law of logarithm, -Log [ H3O+] can also be written as 1/ Log [H3O+].
1/Log [H3O+]
Log [ H3O+] ^-1
-1 Log [H3O+]
- Log [H3O+]
Option B, is valid. 

The correct answer is B ,is not C because of no nrgative sign before log like -logbase10[H3O^+] ,the lack of negative value (-) before log in C makes it wrong ,so the right answer is B

use law of indices.
the law of negative index.
remember that
PH=-log[H+]
removing "- ' making it fraction
PH= Log[ 1/ pH] or log [1/H3O]







