The mathematical expression of PH is

a

log 10[OH-]

b

log 101/[H 3 O+]

c

log 10[H 3 O+]

d

log 101/[OH -]

Download Offline App Ask a Question

Explanation

Correct Option
b

No explanation available

Video Explanation

Post your Contribution

Share:

Discussions (15)

PRadiant
2 years ago

B is correct.
It's just the inverse of its normal value.
Law of logarithm in action.

First, we can actually say H3O+ is the same as H+.
Hence, pH can as well be -Log [H3O+]

Now, from the law of logarithm, -Log [ H3O+] can also be written as 1/ Log [H3O+].

1/Log [H3O+]
Log [ H3O+] ^-1
-1 Log [H3O+]
- Log [H3O+]

Option B, is valid. ✅

israella
5 years ago

Na wa. Wey we go find textbook suitable for this Jamb sef ehn?!!

Victorlinkie
6 years ago

it's actually pH= -log[H+]

josephgnachy
6 years ago

The correct answer is B ,is not C because of no nrgative sign before log like -logbase10[H3O^+] ,the lack of negative value (-) before log in C makes it wrong ,so the right answer is B

De sage
1 year ago

use law of indices.

the law of negative index.

remember that
PH=-log[H+]

removing "- ' making it fraction
PH= Log[ 1/ pH] or log [1/H3O]

ohirocaesar
9 years ago

I think its C

Toepy_LeeCruz
9 years ago

d ans is d

bettyarubi
9 years ago

explaination pls

P.blessed
10 years ago

why not c?

profchudo
9 years ago

very correct

De ansa is D

Sammyporsche123
2 years ago

C✅

Quick Questions

Ask a Question
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments

infinitehoaxx

21st May, 2026

Computer


4 comments