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16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC,...

Chemistry
JAMB 2014

16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3

[Pb = 207, N = 14, O = 16]

  • A. 0.05 g
  • B. 2.00 g
  • C. 1.00 g
  • D. 0.50g
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Correct Answer: Option D
Explanation

molar mass of pb (N0 3) 2 = 331
Mole = \(\frac{16.55}{331}\)= 0.05 mole
∴0.05mole pb (No3)2 dissolved in 1000g H2O x = \(\frac{0.05\times1000}{100}\)= 0.5 mole /dm 3

There is an explanation video available below.


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Explanation Video

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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