16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3

[Pb = 207, N = 14, O = 16]

dandano

7 years ago

Molar mass of Pb(No3)2 =331. Mole=16.55/331=0.05mole. 0.05mole Pb(No3)2 dissolved in 100g H2O. x mole Pb(No3)2 dissolved in 1000g H2O. x=0.05*1000/100= 0.5mole/dm3.

Ejakpovigift

4 years ago

Soulute / solvent * 1000/ molar mass

Use this formula to get your answer

brigelina

7 years ago

the answer is there but the unit differs

Najibutajo1

4 months ago

The chosen Answer is correct = 0.5 mol/dm^3

But the Answer should in dm^3 not in gram

Anela

1 year ago

solubility= m/mm x 1000/vol
m= 16.55
mm= Pb(No3)2
= 207+2(14+3×16)
= 207+2(14+48)
= 207+2(62)
= 207+124= 331
vol.= 100

=16.55/331 x 1000/100

= 16550/33100

= 0.5(ANS)

Najibutajo1

4 months ago

The chosen Answer is correct =

starbaby250

2 years ago

its mol per dm3 not g why are the answers in gram its not correct

Kamsoyolert2

1 year ago

some one should please explain better

Stevenun

1 year ago

😲

Stevenun

1 year ago

mol per dm plyno dey confuse person

Etugo

9 years ago

you guys are confused

ohirocaesar

9 years ago

0.5 approximately 1.00

Samexflex

8 years ago

The answer is there