Correct Answer: Option B

Explanation

CaCO\(_3\) → CaO + CO\(_2\)
CaCO\(_3\) = 40 + 12 + (16 x 3) = 100,

CaO = 40 + 16 = 56
   56g of CaO was produced by 100g of CaCO\(_3\)
∴ 5.6g of CaO will be produced by
(5.6 x 100)/56 = 10g of CaCO\(_3\)

Recall that Number of moles = \(\frac{mass}{molar mass}\)

                                              = \(\frac{10}{100}\)

                                              = 0.10mole

Alternatively,

                                   CaCO\(_3\)    →   CaO   +   CO\(_2\)

                                                          n = \(\frac{m}{M}\)

                                                          n = \(\frac{5.6}{56}\)

                                                          n = 0.10 mole

Since the ratio of the reactant to product is 1 : 1, and the number of mole of CaO is 0.10mole, therefore, the number of mole of CaCO\(_3\) will also be 0.10 mole, according to Avogadro's law.

There is an explanation video available below.

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