How many hydrogen atoms does a single ring cycloalkane have less than the corresponding open-chain alkane?
Let's consider an example:
Cycloalkane → Cyclopropane has the formula CH\(_2\)-CH\(_2\)-CH\(_2\) (when drawn in a cyclic form) = C\(_3\)H\(_6\)
Open chain alkane → Propane has the formula CH\(_3\)CH\(_2\)CH\(_3\) (when drawn on a straight chain) = C\(_3\)H\(_8\)
Comparing the two formulas; C\(_3\)H\(_6\) and C\(_3\)H\(_8\), the difference in the hydrogen atoms is two.
There is an explanation video available below.
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