At S. T. P how many litres of hydrogen can be obtained from the reaction of 500 cm\(^3\) of 0.5 M H\(_2\)SO\(_4\) with excess zinc metal?
(Gram molecular volume of H\(_2\) = 22.4 dm\(^3\))

DBRANDY

11 years ago

Zn + H2SO4 -- ZnSO4 + H2. Covert 500cm^3 to dm^3 = 500/1000 =0.5 dm^3. if 0.5 dm^3 = 22.4 dm^3 thereforo 1 dm^3 = 0.5/1 x 22.4 = 11.2 dm^3 so litre of H2 = 11.2 dm^3 x 0.5 = 5.6 dm^ is correct D

Babskenny

11 years ago

alternativey mettod

500/1000 ×0.5 × d GRAM MOLECULAR VOLUME OF STP 22.4 =5.6Mol dm3

Tumise17

1 year ago

All questions must be explained

Babskenny

11 years ago

alternativey method

500/1000 ×0.5 × d GRAM MOLECULAR VOLUME OF STP 22.4 =5.6Mol dm3

Babskenny

11 years ago

alternativey mettod

500/1000 *0.5 * d GRAM MOLECULAR VOLUME OF STP 22.4