Which of the following mixtures would result in a solution of pH greater than 7?
25.00 cm3 of 0.05 M H2SO4 and 25.00cm3 of 0.50 M Na2CO3
25.00 cm3 of 0.05 M H2SO4 and 25.00 cm3 of 0.10 M NaHCO3
25.00 cm3 of 0.11 MH2SO4 and 25.00cm3 0. 10 M NaOH
25.00cm3 of 0.11 MH2 SO4 and 50.00 cm3 of 0.05 M NaOH
25.00cm3 of 0.25 M H2SO4 and 50.00cm3 of 0.20 M NaOH
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Discussions (18)
actually the current option is between option a and option c now let's calculate 4 d no. of mole of acid and base in both option a and c
In option A.. No. of mole of acid=25×0.05=1.25
for the mole of base=25×0.5=12.5
Now! from our calculation you can see that the number of mole of base is greater than the number of the mole of acid
let's calculate how much more the number of mole of the base is greater than the number of mole of the acid=mole of base/mole of Acid=12.5/1.25=10
so, the base is 10 times greater than that of the acid ☑️
Now let's look at option E
Mole of acid=25×0.25=6.25
mole of base=50×0.2=10
mole ratio=base/acid=10/6.25=1.6
From our calculation so far.
we see that the mole ratio of the base in option E is nt as large as in option A.
Since option A has higher mole of base .The reaction will be alkaline which will be greater than 7.
That makes option A the the most viable option ☑️
* Strong Acid vs. Weak Base: In option A, we have a strong acid (H₂SO₄) and a weak base (Na₂CO₃). While the base is in excess, it's important to remember that weak bases don't ionize completely in solution. This means that not all of the Na₂CO₃ will contribute to raising the pH.
* Strong Acid vs. Strong Base: In option E, we have a strong acid (H₂SO₄) and a strong base (NaOH). Strong bases dissociate completely, meaning all of the NaOH will contribute to raising the pH.
Since the question asks for the mixture that results in a pH greater than 7, I would be more confident that option A, with the excess weak base, would create a more basic solution.
While option E also results in a basic solution, the slight excess of the strong base might not raise the pH as significantly as the excess weak base in option A.
Therefore, to be safe, I would choose option A.
The neutralization of a strong acid and weak base will have a pH of less than 7, and conversely, the resulting pH when a strong base neutralizes a weak acid will be greater than 7
therefore, option A is correct, because Na2CO3 is a strong base
