An element, Z froms an anion whose formula is [Z(CN)₆]^y. If Z has an oxidation number of +2, what is the value of y?

Maduanthonyii

5 years ago

Cyanide (CN) is an anion with the charger -1.
If Z has a cation of +2. Substituting the values, we have: [2+6(-1)]=y; -4=y therefore y equals -4 Option C.

sandra4christ1997

9 years ago

I don't know why if I want to solve 250 questions, when I solve like hundred ans ten questions, and press nest another thing will display on the screen,all my labour to solve those question will be in vain

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Slimmie_rex

9 years ago

pls I need explanation

CBA

7 years ago

How?

BlaqOmah

2 months ago

CN has a charge of –1 and Z +2 as we re told. imputing the values we have that. 2+(–1×6)=y
2–6=y
y=–4

Bhobhoyinkosa

6 months ago

The reason why the answer is -4, us because of the six in the bracket